Answer
See explanation.
Work Step by Step
a. The frequency is $f=\frac{c}{\lambda}=5.94\times10^{14}Hz $.
b. $$ E=hf=h\frac{c}{\lambda}$$
$$E=\frac{1.24\times10^{-6}eV\cdot m}{505\times10^{-9}m}=2.46 eV=3.94\times10^{-19}J$$
c. $K=\frac{1}{2}mv^2$, so solve for $v=\sqrt{\frac{2K}{m}}=9.1mm/s$.
