University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 38 - Photons: Light Waves Behaving as Particles - Problems - Exercises - Page 1275: 38.1

Answer

See explanation.

Work Step by Step

The frequency is $f=\frac{c}{\lambda}=5.77\times10^{14}Hz $. The momentum is $p=\frac{h}{\lambda}$ $$p=\frac{6.626\times10^{-34}J \cdot s}{(520\times10^{-9}m) }= 1.27\times10^{-27}kg \cdot m/s $$ $$ E=hf=h\frac{c}{\lambda}$$ $$E=\frac{1.24\times10^{-6}eV\cdot m}{520\times10^{-9}m}=2.38 eV$$
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