Answer
92.5 m.
Work Step by Step
The interval, measured on Coruscant with the ship stopped, is the proper length $\mathcal{l}_o$.
The value of $\gamma$ is $\frac{1}{\sqrt{1-u^{2}/c^{2}}}=1.25$.
The scientist originally measures a contracted length of $\frac{\mathcal{l}_o }{\gamma}=74.0 m$.
Later she will measure $\mathcal{l}_o=(\gamma)(74.0m)=92.5 m$.
