Answer
See explanation.
Work Step by Step
a. The value of $\gamma$ is $\frac{1}{\sqrt{1-u^{2}/c^{2}}}=1.009$.
The pilot measures a contracted length of $\frac{3600m}{\gamma}=3568 m$.
b. $t=\frac{L}{v}=\frac{3600m}{4.00\times10^7m/s}=9.00\times10^{-5}s$.
c. Calculate the time by using kinematics.
$\frac{L}{v}=\frac{3568m}{4.00\times10^7m/s }=8.92\times10^{-5}s $.
