University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 35 - Interference - Problems - Exercises - Page 1181: 35.23

Answer

114 nm.

Work Step by Step

See figure 35.11. Both rays undergo a $180^{\circ}$ phase change on reflection. There is no net phase difference introduced and the condition for destructive interference is $2t=(m+\frac{1}{2})\lambda$. For the thinnest film, m=0. $$t=\frac{\lambda}{4} $$ Note that $\lambda=\frac{\lambda_0}{1.42}$. $$t=\frac{\lambda_0}{4(1.42)}=\frac{650nm}{4(1.42)}=114 nm $$
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