Answer
1670 radians.
Work Step by Step
The phase difference is $\phi=(\frac{2\pi d}{\lambda})(sin \theta)$.
$$\phi=(\frac{2\pi (0.340\times10^{-3}m)}{500\times10^{-9}m})(sin 23.0^{\circ})=531.4 \pi \; rad$$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 35 - Interference - Problems - Exercises - Page 1181: 35.19
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