University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Exercises - Page 1153: 34.47

Answer

8.7 cm. No.

Work Step by Step

Use the lens equation. $$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$ $$\frac{1}{3.90m}+\frac{1}{s’}=\frac{1}{0.085m}$$ $$s’=0.0869m$$ Calculate the magnification. $$m=-\frac{s’}{s}=-\frac{0.0869m }{3.90m}=-0.0223$$ Find the height of your friend on the sensor. $$|y’|=|m||y|=(0.0223)(1.75m)=0.039m$$ This is too large to fit on the sensor, which is 36mm at its widest.
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