Answer
8.7 cm. No.
Work Step by Step
Use the lens equation.
$$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$
$$\frac{1}{3.90m}+\frac{1}{s’}=\frac{1}{0.085m}$$
$$s’=0.0869m$$
Calculate the magnification.
$$m=-\frac{s’}{s}=-\frac{0.0869m }{3.90m}=-0.0223$$
Find the height of your friend on the sensor.
$$|y’|=|m||y|=(0.0223)(1.75m)=0.039m$$
This is too large to fit on the sensor, which is 36mm at its widest.