University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 34 - Geometric Optics - Problems - Exercises - Page 1153: 34.46

Answer

a. 14.8 cm. b. 1.44 m by 2.16 m.

Work Step by Step

a. Use the lens equation. $$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$ $$\frac{1}{15.0cm}+\frac{1}{900cm}=\frac{1}{f}$$ $$f=14.75cm$$ b. Calculate the magnification. $$m=-\frac{s’}{s}=-\frac{900cm}{15.0cm}=-60$$ Find the minimum dimensions of the screen. $$|y’_1|=|m||y_1|=(60)(24mm)=1440mm$$ $$|y’_2|=|m||y_2|=(60)(36mm)=2160mm$$
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