University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 33 - The Nature and Propagation of Light - Problems - Exercises - Page 1105: 33.18

Answer

a. $38.1^{\circ}$. b. $55.4^{\circ}$.

Work Step by Step

Total internal reflection occurs when the angle of incidence is greater than or equal to the critical angle. At the critical angle, Snell’s law gives $n_{glass}sin\theta_{crit}= n_{air}sin90^{\circ}$. a. $n_{glass}sin\theta_{crit}= n_{air}sin90^{\circ}$ $$1.62sin\theta_{crit}= 1.00 (1)$$ $$\theta_{crit}= 38.1^{\circ}$$ b. Use the same procedure as in part A. $$n_{glass}sin\theta_{crit}= n_{water}sin90^{\circ}$$ $$1.62sin\theta_{crit}= 1.333 (1)$$ $$\theta_{crit}= 55.4^{\circ}$$
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