Answer
See explanation.
Work Step by Step
Apply Snell’s law to the refraction at each interface.
a. $n_a sin\theta_a= n_b sin\theta_b$
$$n_{air} sin\theta_{air}= n_{glass} sin\theta_{glass}= n_{water} sin\theta_{water}$$
$$n_{air} sin\theta_{air}=n_{water} sin\theta_{water}$$
$$1.00 sin35.0^{\circ}=1.333 sin\theta_{water}$$
$$ \theta_{water}=25.5^{\circ} $$
b. As we can see, there is no dependence of the answer upon the glass’s index of refraction.