University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 32 - Electromagnetic Waves - Problems - Exercises - Page 1074: 32.30

Answer

a. The wavelength is 9.30 mm. b. 4.65 mm. c. $v= 2.05\times10^8m/s$.

Work Step by Step

a. The nodal planes of the magnetic field are $\lambda/2$ apart. We are told that distance is 4.65 mm, so the wavelength $\lambda$ is 9.30 mm. b. Adjacent nodal planes of the electric and magnetic fields are the same distance apart, 4.65 mm. c. $v=f\lambda=(2.30\times10^{10}Hz)(9.30\times10^{-3}m)=2.05\times10^8m/s$.
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