University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 32 - Electromagnetic Waves - Problems - Exercises - Page 1074: 32.19

Answer

$2.5\times10^{25}W$.

Work Step by Step

At a distance r from the star, the total average power from the star is spread over a spherical surface, of area $4 \pi r^2$. $$P_{av}=I4\pi r^2$$ $$=(5.0\times10^3W/m^2)(4 \pi)(2.0\times10^{10}m)^2=2.5\times10^{25}W $$
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