University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 3 - Motion in Two or Three Dimensions - Problems - Exercises - Page 95: 3.27

Answer

(a) $a_R = 2.57~m/s^2$ (directed straight up toward the center of the circle) (b) $a_R = 2.57~m/s^2$ (directed straight down toward the center of the circle) (c) It takes 14.7 seconds to make one revolution.

Work Step by Step

(a) $a_R = \frac{v^2}{R} = \frac{(6.00~m/s)^2}{14.0~m}$ $a_R = 2.57~m/s^2$ (directed straight up toward the center of the circle) (b) $a_R = \frac{v^2}{R} = \frac{(6.00~m/s)^2}{14.0~m}$ $a_R = 2.57~m/s^2$ (directed straight down toward the center of the circle) (c) $t = \frac{2\pi ~r}{v} = \frac{(2\pi)(14.0~m)}{6.00~m/s}$ $t = 14.7~s$ It takes 14.7 seconds to make one revolution.
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