Answer
a) The current is $$I = 2.61 A$$
b) The drift velocity is $$v_{d} = 2.353\times10^{-4} m/s$$
Work Step by Step
$J = \frac{I}{A}$. "J" represents the current density. "I" representes the current and "A" represents the cross-sectional area which is given by:
$A = \frac{π}{2}d^{2}$
$A = \frac{π}{2}(1.02\times10^{-3}m)^{2}$
$A = 8.17\times10^{-7}m^{2}$
Since $I=JA$, the current is $$I = (3.2\times10^{6}A/m^{2}) \times 8.17\times10^{-7}m^{2}$$ $$I = 2.61 A$$
The drift velocity is given by the following formula: $v_{d} = \frac{J}{nq}$
Therefore, the drift velocity is $$\frac{ (3.2\times10^{6}A/m^{2})}{8.5\times10^{28}electrons\times1.6\times10^{-19}C}$$
$$v_{d} = 2.353\times10^{-4} m/s$$
