University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 25 - Current, Resistance, and Electromotive Force - Problems - Exercises - Page 842: 25.14

Answer

$ ρ = 1.47\times10^{-8} m$ According to the table in the textbook (Table 25.1), the wire is made out of silver since silver closely matches the resistivity of the wire.

Work Step by Step

$A = \frac{π}{4}\times d^{2}$ $A = \frac{π}{4}\times (2.05\times10^{-3}m)^{2}$ $A = (3.3\times10^{-6}m^{2}$). This area represents the cross sectional area of the wire. The resistivity of a wire is given by the following formula: $ρ = \frac{RA}{L}$ $$ρ = \frac{0.0290 Ω\times3.3\times10^{-6}m^{2}}{6.50m}$$ $$ρ = 1.47\times10^{-8} m$$
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