Chapter 20 - The Second Law of Thermodynamics - Problems - Exercises - Page 677: 20.18

$W = 4.89 \times 10^3 J$

To find the work performed by the engine, we need to find the $Q_C$ and $Q_H$ first $Q_C = -mL_F$ $Q_C = −(0.0400 kg)(334×10^3 J/kg) $ $Q_C = −1.336×10^4 J$ $Q_H = -(−1.336×10^4 J) \frac{373.15 K}{273.15 K} $ $Q_H = -1.866 \times 10^4 J$ $Q_H = 1.825 \times 10^4 J$ $W = Q_C + Q_H$ $W = −1.336×10^4 J + 1.825 \times 10^4 J$ $W = 4.89 \times 10^3 J$