Answer
(a) $Q = ā8.09 Ć 10^5 J $
(b) $|W| = 3.37 Ć 10^5 J $
(c) $|š_š»| = 1.15 \times 10^6 J $
Work Step by Step
(a) Amount of heat must be removed from the water
$Q = mc_{ice}ĪT_{ice} ā mL_f + mc_wĪT_w$
$Q = (1.80 kg) [(2100 J/kgā
K)(ā5.0 Ā°C) ā 3.34Ć10^5 J/kg + (4190 J/kg ā
K)( ā25.0 CĀ°)]$
$Q = ā8.09 Ć 10^5 J $ The negative sign indicates heat is removed from the water.
(b) Energy consumed in terms of Work
$K = \frac{Q_C}{|W|}$
$|W| = \frac{ā8.09 Ć 10^5 J }{2.40 }$
$|W| = 3.37 Ć 10^5 J $
(c) $|š_š»| = W + |š_š¶|$
$|š_š»| = 3.37 Ć 10^5 J + 8.09 Ć 10^5 J $
$|š_š»| = 1.15 \times 10^6 J $