University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 60: 2.33

Answer

The speed of the block 3.40 meters down the incline is 2.7 m/s

Work Step by Step

Note that 3.40 m is half of 6.80 m. Let $v_2 = 3.80~m/s$ and let $x_2 = 6.80~m$ $v_2^2 = 2ax_2$ $v_2 = \sqrt{2ax_2}$ Let $v_1$ be the speed at $3.40~m$ and let $x_1 = 3.40~m$ $v_1 = \sqrt{2ax_1} = \sqrt{2a(x_2/2)} = \frac{1}{\sqrt{2}}\sqrt{2ax_2}$ $v_1 = \frac{v_2}{\sqrt{2}} = \frac{3.80~m/s}{\sqrt{2}}$ $v_1 = 2.7~m/s$ The speed of the block 3.40 meters down the incline is 2.7 m/s
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.