Answer
0.38 m
Work Step by Step
We use the equation,
$v=v_{0}+at$,
Since,$v=0, v_{0}=-at$,
Now,
$x=v_{0}t+\frac{1}{2}at^{2}$,
$x=(-at)t+\frac{1}{2}at^{2}$,
$x=-\frac{1}{2}at^{2}$. $ \,\,\,\,\,Equation \,1$
$a=-60g=-60\times9.8=-588m/s^{2}$
Also, $t=36\times10^{-3}$
So, from Equation 1, $x=\frac{588}{2}\times(36\times10^{-3})^{2}$
$=0.38m$.
