University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 13 - Gravitation - Problems - Exercises - Page 425: 13.14


The mass of Rhea is $2.32\times 10^{21}~kg$. The average density of Rhea is $1240~kg/m^3$.

Work Step by Step

We can find the mass of Rhea. $\frac{G~M}{R^2} = 0.265~m/s^2$ $M = \frac{R^2~(0.265~m/s^2)}{G}$ $M = \frac{(7.64\times 10^5~m)^2~(0.265~m/s^2)}{6.67\times 10^{-11}~m^3/kg~s^2}$ $M = 2.32\times 10^{21}~kg$ The mass of Rhea is $2.32\times 10^{21}~kg$. We can find the volume of Rhea. $V = \frac{4}{3}~\pi~R^3$ $V = \frac{4}{3}~\pi~(7.64\times 10^5~m)^3$ $V = 1.87\times 10^{18}~m^3$ We can find the average density of Rhea. $\rho = \frac{Mass}{Volume}$ $\rho = \frac{2.32\times 10^{21}~kg}{1.87\times 10^{18}~m^3}$ $\rho = 1240~kg/m^3$ The average density of Rhea is $1240~kg/m^3$.
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