## University Physics with Modern Physics (14th Edition)

(a) The acceleration due to gravity on the surface of Venus is $8.87~m/s^2$. (b) The weight of the rock on the surface of Venus is 67.9 N.
(a) Let $M$ be the mass of the earth. Let $R$ be the radius of the earth. We can write an expression for the acceleration due to gravity on the earth's surface. $\frac{G~M}{R^2} = 9.80~m/s^2$ We can find the acceleration due to gravity on Venus. $\frac{(G)(0.815~M)}{(0.949~R)^2} = \frac{0.815}{(0.949)^2}~(9.80~m/s^2)$ $\frac{(G)(0.815~M)}{(0.949~R)^2} = 8.87~m/s^2$ The acceleration due to gravity on the surface of Venus is $8.87~m/s^2$. (b) We can find the mass of the rock. $m = \frac{75.0~N}{9.80~m/s^2}$ $m = 7.65~kg$ We can find the weight of the rock on the surface of Venus. $weight = (7.65~kg)(8.87~m/s^2)$ $weight = 67.9~N$ The weight of the rock on the surface of Venus is 67.9 N.