Answer
(a) 1.62 N
(b) 1.80 ×10^3 rev/min
(c) If the figure in the problem is viewed from above, τ is in the direction of the precession and L is along the axis of the rotor, away from the pivot.
Work Step by Step
(a) Fp = wtot = (0.165 kg)(9.80 m/s2 ) = 1.62 N
(b) ω = wr/IΩ = (0.165 kg)(9.80 m/s2 )(0.0400 m)/(1.20×10−4 kg⋅m2)(2.856 rad/s) = 189 rad/s = 1.80 ×10^3 rev/min
(c) If the figure in the problem is viewed from above, τ is in the direction of the precession and L is along the axis of the rotor, away from the pivot.
