Answer
$\vec{A}=0\hat{i}-8.00m\hat{j}$
$\vec{B}=7.50m \hat{i}+13.0m \hat{j}$
$\vec{C}=-10.9m \hat{i}-5.07m \hat{j}$
$\vec{D}=-7.99m\hat{i}+6.02m\hat{j}$
Work Step by Step
The general expression for a vector is given in equation 1.14.
Use $ V_x=Vcos\theta, V_y=Vsin\theta $. The angles are 270, 60, 205, and 143 degrees, respectively, and the magnitudes are in the diagram.
$A_x=0, A_y=-8.00m, B_x=7.50m, B_y=13.0m, C_x=-10.9m, C_y=-5.07m, D_x=-7.99m, D_y=6.02m$.
