Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 7 - Entropy - Problems - Page 406: 7-126

Answer

a) $\eta=81.9\%$ b) $T_{2,s}=505.5\ K$

Work Step by Step

From table A-17: Inlet ($T_1=300\ K$): $P_{r1}=1.386,\ h_1=300.19\ kJ/kg$ Outlet ($T_2=550\ K$): $h_{2,a}=554.74\ kJ/kg$ $\dfrac{P_{r2}}{P_{r1}}=\dfrac{P_{2}}{P_{1}},\quad P_1=95\ kPa,\ P_2=600\ kPa$ $P_{r2}=8.754\overset{\small\mbox{A-17}}{\rightarrow}h_{2,s}=508.72\ kJ/kg,\ T_{2,s}=505.5\ K$ $\eta=\dfrac{h_{2,s}-h_1}{h_{2,a}-h_1}$ $\eta=81.9\%$
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