Answer
$\dot{W}=274\ kW$
Work Step by Step
$\dot{W}=\dot{m}(\int vdP+\Delta ke + \Delta pe)$
$\dot{W}=\dot{m}v_1(P_2-P_1)$
Given $\dot{m}=45\ kg/s,\ v_1=0.001017\ m^3/kg,\ P_2=6000\ kPa,\ P_1=20\ kPa$
$\dot{W}=274\ kW$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 7 - Entropy - Problems - Page 405: 7-105
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