Answer
$w=205.6\ kJ/kg$
Work Step by Step
From table A-4:
Inlet ($x_1=1, T_1=150°C$): $P_1 = 476.16\ kPa,\ v_1=0.39248\ m³/kg$
$w=\int vdP$
Constant specific volume: $w=v(P_2-P_1)$
Given $P_2=1000\ kPa$
$w=205.6\ kJ/kg$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 7 - Entropy - Problems - Page 404: 7-103
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