Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 323: 6-139

Answer

$F_s=29.1\ gal/year$

Work Step by Step

$\dot{m}=1\ kg/L\times(13.3-10.5)L/min\times6min/person.day\times 4\ persond\times 365\ days$ $\dot{m}=24528\ kg/year$ $E=\dot{m}c\Delta T,\ c=4.18\ kJ/kg.°C,\ \Delta T=(42-15)°C$ $E_s=2.768\ GJ/year$ $E_s=F_s \times \epsilon\times q,\ \epsilon=0.65,\ q=146300\ kJ/gal$ $F_s=29.1\ gal/year$ $M_s=F_s\times p_f,\ p_f=\$2.80/gal$ $M_s=\$ 81.5/year$
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