Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 323: 6-135

Answer

$P_H/P_L=3.25$

Work Step by Step

$COP_{HP}=\dfrac{1}{1-\frac{T_L}{T_H}},\quad \frac{T_H}{T_L}=1.2$ $COP_{HP}=6.0$ $COP_{HP}=\dot{Q}_H/\dot{W}_i,\ \dot{W}_i=5\ kW$ $\dot{Q}_H=30.0\ kJ/s=q.\dot{m},\quad \dot{m}=0.22\ kg/s$ $q=136.36\ kJ/kg=\Delta h_v$ From table A-11: $T_H=62.0°C=335\ K,\ P_H=1764\ kPa$ $T_L=291.4\ K=18.3°C,\ P_L=542\ kPa$ $P_H/P_L=3.25$
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