Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 267: 5-158

$\dot{Q}=1.90\ kW$

$\dot{m}=\rho(\dfrac{\pi D^2}4)\mathcal{V}$ $\rho=2702\ kg/m³,\ D=0.005\ m,\ \mathcal{V}=8\ m/min$ $\dot{m}=0.4244\ kg/min=0.007074\ kg/s$ $\dot{m}h_1=\dot{m}h_2+\dot{Q}$ $\dot{Q}=\dot{m}c_p(T_1-T_2)$ $c_p=0.896\ kJ/kg.°C,\ T_1=350°C,\ T_2=50°C$ $\dot{Q}=1.90\ kW$