Answer
$T_1=4.2°C$
Work Step by Step
$mh_1=mh_2+Q$
$Q=mc_p(T_1-T_2)$
$Q=15\ kJ/kg \times 3\ kg=45\ kJ,\ c_p=4.18\ kJ/kg.°C,\ m=1\ kg,\ T_2=15°C$
$T_1=4.2°C$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 267: 5-157
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