Answer
$\dot{m}=0.0238\ kg/s$
Work Step by Step
From the energy balance in the water:
$\dot{Q}+\dot{m}h_1=\dot{m}h_2$
$\dot{Q}=\dot{m}\Delta h_v$
Given $\dot{Q}=48\ kJ/s,\ \Delta h_v=2014.2\ kJ/kg$
$\dot{m}=0.0238\ kg/s$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 266: 5-146
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