Answer
$w_{flow}=816.2\ kJ/kg$
$T_t=655.0\ K$
Work Step by Step
For ideal gases:
$Pv=RT=w_{flow}$
Given $R=2.0769\ kJ/kg.K,\ T_L=120°C=393\ K$:
$w_{flow}=816.2\ kJ/kg$
For discharges $h_{line}=u_{tank}$
$c_{p,L}T_L=c_{v,t}T_t$
Given $c_{p,L}=5.1926\ kJ/kg.K,\ c_{v,t}=3.1156\ kJ/kg.K$:
$T_t=655.0\ K$
