Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 254: 5-21

Answer

$\dot{Q}=3.46\ kW$

Work Step by Step

From tables A-12, and A-13: Inlet ($P_1=0.14\ MPa$, saturated vapor): $h_1=239.19\ kJ/kg$ Outlet ($P_2=0.8\ MPa,\ T_2=60°C$): $h_2=296.82\ kJ/kg$ $\dot{Q}=\Delta \dot{H}=\dot{m}(h_2-h_1)$ Since $\dot{m}=0.06\ kg/s$: $\dot{Q}=3.46\ kW$
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