Answer
$\dot{Q}=0.945\ kW$
Work Step by Step
The mass flow rate can be given by:
$P\dot{V}_1=\dot{m}RT_1$
Given $P=101.325\ kPa,\ R=0.287\ kJ/kg.K,\ T=297 K,\ \dot{V}=150\ m³/h=0.04167\ m³/s$:
$\dot{m}=0.0495\ kg/s$
The heat loss:
$\dot{Q}=\Delta \dot{H} = \dot{m}c_p(T_2-T_1)$
With $c_p=1.005\ kJ/kg.K,\ T_1=5°C, T_2=24°C$
$\dot{Q}=0.945\ kW$
