Answer
$\Delta m = 8.24kg $
Work Step by Step
#1
$m_{1} = S_{1}V_{1} $
$m_{1} = 1.18 \times 2$
$m_{1} = 2.36kg$
#2
$m_{2} = S_{2}V_{2} $
$m_{2} = 5.3 \times 2 $
$m_{2} = 10.6kg $
#3
$\Delta m = m_{2}-m_{1}$
$\Delta m = 8.24 kg$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 252: 5-9
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