Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 252: 5-5

Answer

Venting Mass flow rate = 0.036 kg/sec Vented mass in a day = 3110.4 kg

Work Step by Step

1# Venting Mass flow rate = Density*Volume flow rate Venting Mass flow rate= $1.2 kg/m^{3} \times 30 \times 10^{-3} m^{3}/sec$ Venting Mass flow rate= 0.036 kg/sec #2 Vented mass in a day = $0.036 kg/sec \times 24 \times 3600 sec$ Vented mass in a day= 3110.4 kg
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