Answer
E
Work Step by Step
Since $\Delta T(°F)=1.8\Delta T(°C)$
$c=3.6 kJ/kg.°F\times \frac{1.8 °F}{1°C}=6.48\ kJ/kg.°C$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 209: 4-144
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