Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 209: 4-142

Answer

a) $\Delta U=1645\ MJ$ b) $\Delta U=626.4\ MJ$ c) $\Delta U=400.0\ MJ$

Work Step by Step

a) Assuming only phase-change heat: $\Delta U=V.\Delta \hat{h}_v$ Given $V=5000L,\ \hat{h}_v=329\ kJ/L$: $\Delta U=1645\ MJ$ b)$\Delta U=mc_v\Delta T=\rho Vc_v\Delta T$ Given $V=5\ m³,\ \rho=2700\ kg/m³,\ c_v=2.32\ kJ/kg.°C,\ \Delta T=20°C$: $\Delta U=626.4\ MJ$ c) b)$\Delta U=mc_v\Delta T=\rho Vc_v\Delta T$ Given $V=5\ m³,\ \rho=1000\ kg/m³,\ c_v=4.0\ kJ/kg.°C,\ \Delta T=20°C$: $\Delta U=400.0\ MJ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.