Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 206: 4-117

Answer

$R=2.075\ kJ/kg.K$ $M=4.007\ kg/kmol$ $c_v=3.111\ kJ/kg.K$ $c_p=5.186\ kJ/kg.K$

Work Step by Step

Since for a constant-pressure process on an ideal gas: $W_b=mR\Delta T$ Given $W_b=16.6\ kJ,\ m=0.8\ kg,\ \Delta T=10K$ solving for R: $R=2.075\ kJ/kg.K$ Since: $R_u=8.314\ kJ/kmol.K=R.M$ $M=4.007\ kg/kmol$ For ideal gases : $c_v=\frac{R}{k-1}$ With $k=1.66$: $c_v=3.111\ kJ/kg.K$ Since: $c_p=c_v+R$ $c_p=5.186\ kJ/kg.K$
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