Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 4 - Energy Analysis of Closed Systems - Problems - Page 202: 4-71

Answer

$W_e = -0.234\ kWh$

Work Step by Step

The energy balance for this system reduces to: $Q_{lost}-W_e=\Delta H= mc_p\Delta T$ With $c_p=1.005\ kJ/kg.K, Q_{lost}=-60\ kJ$ we can solve for $W_e =-843.9\ kJ \times \frac{1\ kWh}{3600\ kJ} = -0.234\ kWh$
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