Answer
$W=450\ kJ$
$Q=12759.1\ kJ$
Work Step by Step
For the initial state (P=75 kPa, saturated with 8% quality):
$v_1 = 0.17833\ m³/kg,\ u_1 = 553.30\ kJ/kg$
Therefore the mass of 2 m³ of steam at this state is:
$m=11.215\ kg$
For the final state (P=225 kPa, V=5 m³):
$v_2=0.446\ m³/kg$
Since $v_L
