Answer
$e_{\%}=0.89\%$
Work Step by Step
From table A-7E:
$h=378.41\frac{Btu}{lbm}$
Using the incompressible liquid aproximation from Table A-4E:
$h_{f}=375.04\frac{Btu}{lbm}$
Then the error is:
$e=\frac{378.41\frac{Btu}{lbm}-375.04\frac{Btu}{lbm}}{378.41\frac{Btu}{lbm}}=0.0089$
$e_{\%}=0.89\%$
