Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 3 - Properties of Pure Substances - Problems - Page 155: 3-55E

Answer

a)$P=29.844psia$ b)$x=0.2193$ c)$h=425.96\frac{Btu}{lbm}$ Process is shown at the image

Work Step by Step

From table A-6E: $\upsilon=3.0433\frac{ft^3}{lbm}$ At the final state as $0.017\frac{ft^3}{lbm}\lt \upsilon\lt 13.816\frac{ft^3}{lbm}$ is a saturated mixture. a)$P=29.844psia$ b)$x=\frac{3.0433\frac{ft^3}{lbm}-0.017\frac{ft^3}{lbm}}{13.816\frac{ft^3}{lbm}-0.017\frac{ft^3}{lbm}}=0.2193$ c)$h=218.63\frac{Btu}{lbm}+0.2193*945.41\frac{Btu}{lbm}=425.96\frac{Btu}{lbm}$
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