Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 108: 2-139

e) $2834W$

First we calculate the area of the wall: $A=7m*10m=70m^2$ Knowing that the heat transfer in this case is by conduction: $Q_{cond}=\frac{kA\Delta T}{L}=\frac{0.92\frac{W}{m^{\circ}C}*70m^2*(15^{\circ}C-4^{\circ}C)}{0.25m}=2833.6W$