Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 106: 2-117

Answer

$m_{lead}=6693.75\frac{kg}{year}$

Work Step by Step

The amount of lead put into the atmosphere per year in that city will be: $m_{lead}=0.5*70000car*15000\frac{km}{car,year}*\frac{8.5L}{100km}*0.15\frac{g}{L}$ $m_{lead}=6693.75\frac{kg}{year}$
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