Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 105: 2-112

Answer

$Cost_{saved}=11.286*10^9dollars$

Work Step by Step

The money saved will be: $Cost_{saved}=570000\frac{barrels}{day}*110\frac{dollars}{barrel}*180\frac{days}{year}=11.286*10^9dollars$
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