Answer
$m=49483.88\frac{kg}{s}$
Work Step by Step
Here we are working with potential energy:
$W_{p}=mgh$
Solving for $m$:
$m=\frac{W_{p}}{gh}=\frac{100*10^6W}{9.81\frac{m}{s^2}*206m}=49483.88\frac{kg}{s}$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 102: 2-73
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