Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 43: 1-48E

Answer

$29.0 psia$

Work Step by Step

$P = (1500 mmHg)(\dfrac{0.1333kPa}{1mmHg})(\dfrac{1psia}{6.895kPa}) = 29.0 psia$
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