Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 43: 1-52E

Answer

a) $P=2.78psi$ b) $P=5.56psi$

Work Step by Step

$P=\frac{F}{A}$ $F=200lbf$ in both cases a) $A=72in^2$ Then $P=\frac{200lbf}{72in^2}=2.78psi$ b) $A=\frac{72in^2}{2}=36in^2$ Then $P=\frac{200lbf}{36in^2}=5.56psi$
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