Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems: 1-14

Answer

$12kWh$ $43200kJ$

Work Step by Step

First we determine the amount of electric energy used in $kWh$: $E=(4kW)*(3h)=12kWh$ Now to determine the amount of electric energy used in $kJ$: $4kW = 4\frac{kJ}{s}$ and $3h*\frac{3600s}{h}=10800s$ Then the energy is: $E=(4\frac{kJ}{s})*(10800s)=43200kJ$
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